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发表于 2005-8-23 20:29 | 显示全部帖子
楼上说的没错，如果不改变选择后面是汽车的几率是三分之一，改变后几率是三分之二。
Debugging is twice as hard as writing the code in the first place. Therefore,if you write the code as cleverly as possible,you are, by definition,not smart enough to debug it.-- Brian W. Kernighan
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Lightningbolt

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发表于 2005-8-23 23:55 | 显示全部帖子
Originally posted by 驴子 at 2005-8-23 21:12:

如果改成4扇门，第一次选择后主持人打开2扇门呢




如果其他条件都不变的话，我觉得结果应该还是更换的几率更大，不更换几率是2/5，更换几率是3/5，不知道对不对。
Debugging is twice as hard as writing the code in the first place. Therefore,if you write the code as cleverly as possible,you are, by definition,not smart enough to debug it.-- Brian W. Kernighan

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Lightningbolt

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发表于 2005-8-24 00:11 | 显示全部帖子
恩，刚才按正常算法又算了一下，应该是1/4和3/4。其实按照前面的思维的话，马上就能得到答案，一个概率不变，另一个是它的补。
Debugging is twice as hard as writing the code in the first place. Therefore,if you write the code as cleverly as possible,you are, by definition,not smart enough to debug it.-- Brian W. Kernighan

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